Question

a 5000 gallon tank is leaking at a rate of 1 cup per secondconvert 1 cup/sec to gallons/hourabout how many hours until the tank is empty round to the nearest whole number

Answer 1

1 cup/sec = 225 gallons/hour

The tank will be empty in 22.22 hours.

Step-by-step explanation

To do this, we need to first note that

1 gallon = 16 cups

1 hour = 3600 seconds

So,

`\begin{gathered} 1\frac{\text{cup}}{\sec }*\frac{1\text{ gallon}}{16\text{ cups}}*\frac{3600\text{ sec}}{1\text{ hour}} \\ =(1*1*3600)/(16)(gallon)/(hour) \\ =225\text{ gallons/hour} \end{gathered}`

So, now, we can then calculate how many hours it will take the tank to become empty.

The tank has a volume of 5000 gallons

Rate of leakage = (Number of gallons)/(Number of hours)

Rate of leakage = 1 cup/sec = 225 gallons/hour

Number of gallons = 5000

Number of hours = ?

`\begin{gathered} \text{Rate of leakage = }\frac{Number\text{ of gallons}}{Number\text{ of hours}} \\ 225=\frac{5000}{\text{Number of hours}} \\ \text{Number of hours = }(5000)/(225)=22.22\text{ hours} \end{gathered}`

Hope this Helps!!!