Question

Let g(x) = 3x+2 and f(x)= (x-2)/3. Find the value. f(g(0))a) 0b) -2/3c) 1d) -1

Answer 1

We have two functions:

`\begin{gathered} g\mleft(x\mright)=3x+2 \\ f\mleft(x\mright)=(x-2)/(3) \end{gathered}`

We have to calculate f(g(0)).

We can do it like this:

`\begin{gathered} f(g(0))=(g(0)-2)/(3) \\ f(g(0))=(\lbrack3(0)+2\rbrack-2)/(3) \\ f(g(0))=(0+2-2)/(3) \\ f(g(0))=(0)/(3) \\ f(g(0))=0 \end{gathered}`

Answer: a) 0