Question

air.4. A train travels a distance of 2650 kilometers. If the train left the station at 2:00 PM andarrived at its destination at 9:00 PM, what was its average speed? (Express your answer in m/s)

Answer 1

Answer:

Average speed = 105.2 m/s

Step-by-step explanation:

The distance = 2650 kilometers

Convert the distance to meters by multiplying the distance by 1000

`\begin{gathered} \text{The distance =2}650\text{ }*\text{ 1000} \\ \text{The distance = }2650000\text{ m} \end{gathered}`

Departure time = 2:00 PM

Arrival time = 9:00 PM

Time taken for the journey = 9:00 - 2:00

Time taken for the journey = 7 hours

Convert the time to seconds by multiplying by 3600

Time taken = 7 x 3600

Time taken = 25200 seconds

Average speed = (Distance) / (Time taken)

Average speed = 2650000 / 25200

Average speed = 105.2 m/s