Question

A soap bubble (n = 1.33) is 215 nm thick.What is the longest (m = 1) wavelengthIN NANOMETERS that gives a MINIMUM(destructive interference) at that point?(Hint: If you leave the wavelength in nm,the answer will be in nm. No conversionnecessary.)(Unit = nm)

Answer 1

Given:

• n = 1.33

,

• Thickness, t = 215 nm

,

• m = 1

Let's find the longest wavelength in nanometers.

Apply the formula for the destructive interference:

`m\lambda=2nt`

Where:

λ is the wavelength

n = 1.33

t = 215 nm

m = 1

Rewrite the formula for λ, plug in the values of the variables and solve:

`\begin{gathered} \lambda=(2nt)/(m) \\ \\ \lambda=(2*1.33*215)/(1) \\ \\ \lambda=571.9\text{ nm} \end{gathered}`

Therefore, the longest wavelength that gives a minimum at that point is 571.9 nm.

• ANSWER:

571.9 nm