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Statistics. Hi! I need the answer for this:The latest math quiz had an average score of 83.2 with a standard deviation of 3.4. What percent of students scored between a 79.8 and 86.6?

User Izabel
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5 votes

Answer:


68.27\text{ \%}

Step-by-step explanation:

Here, we want to get the percentage of students that scored between the two scores

To get this, we need the z-scores of the given scores

Mathematically, we can calculate the z-scores as follows:


\begin{gathered} z\text{ = }(x-\mu)/(\sigma) \\ \\ \mu\text{ = mean = 83.2} \\ \sigma\text{ = standard deviation = 3.4} \end{gathered}

Now, we calculate the z-score for each of the scores. We call the first z1 and the second z2

We proceed as follows:


z_1=(79.8-83.2)/(3.4)\text{ = -1}

For the second score, we have:


z_2\text{ = }(86.6-83.2)/(3.4)\text{ = 1}

Finally, what we have to do is to find the probability between the two z-scores

We have this as follows:

[tex]P\mleft(-1The values of the z-score are obtained from the probability distribution table

User Altso
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