Question

There is a population of 1,500 bacteria in a colony. If the number of bacteria doubles every33 minutes, what will the population be 66 minutes from now?bacteriaSubmitWork it outNot feeling ready yet? This can help:Describe linear and exponential growth and decay

Answer 1

Given data:

Initial population = 1,500

For every 33 minutes the population doubles.

The first step will be to write a function that models this statement

The model is given as

`\begin{gathered} y=1500(2^{(t)/(33)})^{} \\ \text{Where t is the initial time},\text{ y= final population} \\ \end{gathered}`

The next step will be to find the population of the bacteria at time t=66 minutes.

This will be obtained by substituting t=66 into the equation

`y=1500(2^{(66)/(33)})`

`y=1500(2^2)`

=>

`y=1500(4)`

=>

`y=6000`

Therefore the population of the bacteria after 66 minutes will be 6,000