1 Answer

Naraen · Answer 1 · 2023-12-15T00:00:18+0000

Given,

The diagram of the triangle is shown in the question.

For first diagram,

$\begin{gathered} AC=DE \\ \angle A=\angle E \\ \angle B=\angle F \\ \therefore\Delta ABC\cong\Delta\text{DEF} \end{gathered}$

The triangles are congruent by Angle-angle-side (AAS) property.

For second diagram,

$\begin{gathered} UW=XY \\ \angle U=\angle X \\ \angle W=\angle Y \\ \therefore\Delta UVW\cong\Delta\text{XYZ} \end{gathered}$

The triangles are congruent by Angle-side-angle (ASA) property.

For third diagram,

$\begin{gathered} GI=JK \\ GH=KL \\ IH=JL \\ \therefore\Delta GHI\cong\Delta\text{JKL} \end{gathered}$

The triangles are congruent by Side-side-Side (SSS) property.

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