Johnson, this is the solution to the problem:
We have two dice, each labeled 1 to 6.
In consequence, the highest sum after rolling the dices is 12 and the lowest is 2.
For calculating the sample space, we use:
6 (Numbers of the first dice) * 6 (Numbers of the second dice)
Sample space = 6 * 6 = 36
Now, let's find what are the options to have a sum of 4:
• 1 (First dice) + 3 (Second dice)
,
• 2 (First dice) + 2 (Second dice), the order does not matter.
,
• 3 (First dice) + 1 (Second dice)
Therefore, the probability Brandon's roll will have a sum of 4 is:
3/36 or 1/12 (simplfying).