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Number 4 Find the limit and use the x values : -0.03, -0.02,-0.01,0,0.01,0.02,0.03

Number 4 Find the limit and use the x values : -0.03, -0.02,-0.01,0,0.01,0.02,0.03-example-1

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EXPLANATION

First, let's represent the table with some values of x and y near to the limit:

x y

-0.03 0.66

-0.02 0.65

-0.01 0.64

0.01 0.63

0.02 0.62

0.03 0.62

Now, we need to plot the function:


\mathrm{Plug\: in\: the\: value}\: x=0
=(\sin\left(0+(\pi)/(2)\right)-\sin\left(0\right))/((\pi)/(2))
\sin \mleft(0+(\pi)/(2)\mright)-\sin \mleft(0\mright)
=(1)/((\pi)/(2))
Applying\text{ the fraction rule:}
=(2)/(\pi)

The limit is 2/π and it does existe because It's defined at x=0

Number 4 Find the limit and use the x values : -0.03, -0.02,-0.01,0,0.01,0.02,0.03-example-1
User Jcamelis
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