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Reed Olsen · Answer 1 · 2023-06-20T02:09:46+0000

Answer

a. 78

Explanation

Given that side PQ is tangent to circle O, then angle Q measures 90 degrees.

The addition of the three interior angles of a triangle is equal to 180 degrees. Applying this to triangle PQO, we get:

$\begin{gathered} m\angle P+m\angle Q+m\angle O=180\degree \\ 12\degree+90\degree+x=180\operatorname{\degree} \\ x=180\operatorname{\degree}-12\degree-90\degree \\ x=78\operatorname{\degree} \end{gathered}$

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