We will start from the top
We have a small right triangle with an angle of measure 30 degrees
and hypotenuse of length 30 feet
We will use the sine ratio to find its horizontal side which is a part of d
![\sin (30)=(d1)/(30)](https://img.qammunity.org/2023/formulas/mathematics/college/5gd3xe8170h7vzpeqcewt09fmuogm9oc76.png)
By using cross multiplication
![\begin{gathered} d1=30\sin (30) \\ d1=15 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/unsoy3drg18d0bxfzowkocz5eii42gsa22.png)
Now we will work on the triangle which has an angle of measure 75 degrees
and the length of its hypotenuse is 200 feet
We will use the cosine ratio because d is adjacent to the angle of 75
![\cos (75)=(d-d1)/(200)](https://img.qammunity.org/2023/formulas/mathematics/college/i3zl04ixc0m23j9vdk9dryz7iveyod6uuh.png)
By using cross multiplication
![d-15=200\cos (75)](https://img.qammunity.org/2023/formulas/mathematics/college/d5pwuay21ykgoj40lfd3o16vc0nuizdf1g.png)
Add 15 to both sides to find d
![\begin{gathered} d=15+200\cos (75) \\ d=66.76380902 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/8e9a3gxz6vy1zdbi2n9hirtfp8isqckf60.png)
The distance d = 66.76 feet