Question

Solve the following algebraic expressions
1) n(n-4) -n(5-n)
2)

Answer 1

`n {}^(2) - 4n - 5n + n { }^(2) \\ = 2n {}^(2) - 9`

Hope it helps

Answer 2

`\huge\boxed{1) 2n^2-9n}`

`\huge\boxed{2) 6c\³ + 4c\²}`

Explanation:

Part 1:

= n(n-4)-n(5-n)

By distributive property

= n² - 4n - 5n + n²

= 2n² - 4n - 5n

= 2n² - 9n

Part 2:

= 4c(3c-c²)-2c²(4-5c)

Distributing brackets

= 12c² - 4c³ - 8c² + 10c³

Combining like terms

= 12c² - 8c² - 4c³ + 10c³

= 4c² + 6c³

= 6c³ + 4c²

`\rule[225]{225}{2}`

Hope this helped!

~AH1807