Prove that tan(45+A)tan(45-A)=1

Srcerer asked Sep 1, 2022

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Srcerer asked Sep 1, 2022

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26 votes

L.H.S

= tan(45° + A).tan(45° + A)

= (1 + tanA)/(1 - tanA) . (1 - tanA)/(1 + tanA)

= 1

= R.H.S

Hope it will help :)

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