Question

A train is traveling at a constant speed in miles per hour. Hours (x) Miles (y) Which equation models the data in the table? 1 20 2 100 O y=20x 3 180 O y = x + 80 4 260 5 340 Oy=60x – 80 O y = = 80x — 60​

Answer 1

Given:

A train is traveling at a constant speed in miles per hour.

The table of value is:

Hours (x) Miles (y)

1 20

2 100

3 180

4 260

5 340

To find:

The equation for the given data table.

Solution:

It is given that the train is traveling at a constant speed in miles per hour. So, it is a linear relationship.

Choose any two point from the given table of value. Let the two points are (1,20) and (2,100). So, the equation of the line is:

`y-y_1=(y_2-y_1)/(x_2-x_1)(x-x_1)`

`y-20=(100-20)/(2-1)(x-1)`

`y-20=(80)/(1)(x-1)`

`y-20=80(x-1)`

Add 20 on both sides.

`y=80(x-1)+20`

`y=80x-80+20`

`y=80x-60`

Therefore, the correct option is D.