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N2+H2---2 NH3?

ASSIGN OXIDATION STATES AND
FIND OXIDIZING AND REDUCING
AGENTS?
Please with steps if possible

N2+H2---2 NH3? ASSIGN OXIDATION STATES AND FIND OXIDIZING AND REDUCING AGENTS? Please-example-1
User Ista
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1 Answer

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9 votes

Answer:

Oxidizing Agent - Nitrogen

Reducing Agent - Hydrogen

Step-by-step explanation:

The equation of the reaction is given as;

N2 + H2 --> 2 NH3

Oxidation Rules:

- The oxidation number of an element in it's free state is Zero. This means oxidation state of N2 and H2 are Zero.

- The oxidation number of a neutral compound is the sum of the oxidation state of the individual elements and is equal to zero.

- Oxidation Number of Hydrogen in a compound/Molecule is 1 except in hydrides where it is -1

This means that oxidation number of H in NH3 = 1

Oxidation state of N in NH3;

x + 3(1) = 0

x = -3

The reducing agent loses electrons. Loss of electrons is represented by increase in oxidation Number. The oxidation number of H increases from 0 to + 1

The Oxidizing agent gains electrons. Gain of electrons is represented by decrease in oxidation Number. The oxidation number of N decreases from 0 to -3

User Piya
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