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Find the area of △LKJ.

Find the area of △LKJ.-example-1
User Jiyoun
by
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1 Answer

12 votes
12 votes

Answer:


A=600\: u^(2)

The correct answer is letter c.

Explanation:

The area equation of a triangle is given by:


A=(bh)/(2) (1)

Where:

b is the base

h is the height

Let's find first the angle MJK (α), using the tangent definition.


tan(\alpha)=(24)/(32)


\alpha=tan^(-1)((24)/(32))


\alpha=36.9^(\circ)

Now, if α = 37° then β (angle JLK) must be:


37^(\circ) + \beta + 90^(\circ)=180^(\circ)


\beta=53^(\circ)

Now, we can find the distance ML using again the tangent definition:


tan(\beta)=(24)/(ML)


ML=(24)/(tan(53))


ML=18

The base of the triangle LKJ will be:


b=32+ML=32+18=50

Therefore, using equation (1) the area of △LKJ will be:


A=(50*24)/(2)


A=600\: u^(2)

The correct answer is c.

I hope it helps you!

User DKSan
by
3.0k points