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I need help please. Solve:2.6 + x < 8.3

User JNM
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1 Answer

3 votes

We need to solve:


2.6+x<8.3

The first step is to subtract "2.6" on both sides:


\begin{gathered} 2.6+x-2.6<8.3-2.6 \\ x+2.6-2.6<5.7 \\ x<5.7 \end{gathered}

On the number line, we have:

Notice that the the dot must be on "5.7" and it must be an opened dot.

I need help please. Solve:2.6 + x < 8.3-example-1
User Jack Singleton
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