Question

As sugar water solution made from 110 grams of sugar( gluecose, molar mass= 180.16 g/mol) and 500 grams of water. What is the molality of this solution?

Answer 1

To solve this question, we have to convert the grams of glucose to moles using its molecular weigth and convert the grams of water to kilograms of water using a conversion factor:

`110gGlucose\cdot(1molGlucose)/(180.16gGlucose)=0.61molGlucose`
`500gH_2O\cdot(1kg)/(1000g)=0.5kgH_2O`

Now, divide the number of moles of glucose by the number of kg of water to find the molality of the solution:

`m=(0.61mol)/(0.5kg)=1.22m`