Question

2(x-3)+3=6x-5 How to solve the above in distributive property

Answer 1

The equation is given as,

`2(x-3)+3=6x-5`

According to the distributive property,

`a\cdot(b-c)=(a\cdot b)-(a\cdot c)`

Applying the property and resolving the parenthesis,

`\begin{gathered} 2(x)-2(3)+3=6x-5 \\ 2x-6+3=6x-5 \\ 2x-3=6x-5 \end{gathered}`

Subtract 2x on both sides,

`\begin{gathered} 2x-3-2x=6x-5-2x \\ -3+0=4x-5 \\ 4x-5=-3 \end{gathered}`

Add 5 on both sides,

`\begin{gathered} 4x-5+5=-3+5 \\ 4x+0=2 \\ 4x=2 \end{gathered}`

Divide both sides by 4,

`\begin{gathered} (4x)/(4)=(2)/(4) \\ x=(1)/(2) \end{gathered}`

Thus, the solution of the given equation is,

`x=(1)/(2)`