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Statements: Segment Addition PostulateSubtraction Property of EqualityDefinition of segments (2nd use)Definition of segments (1st use)Substitution Property (2nd use)Symmetric PropertySubstitution Property (1st use) (Place statements to the right —->)

Statements: Segment Addition PostulateSubtraction Property of EqualityDefinition of-example-1
User Jrutter
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1 Answer

3 votes

Given:

two-Proof are given and it should be named.


\bar{1.VZ}\approx\bar{VY}\text{ and }\bar{\text{WY}}\approx\bar{XZ}

Above proof is by Definition of segments.


2.VZ=VY\text{ and WY}=XZ

Above proof is by Definition of segments.


3.\text{ }VZ=VX+XZ\text{ and VY=}VW+WY

Above proof is by Segment of Addition Postulate.


4.VX=XZ=VW+WY

Above equation is wrong actually it is VX+XZ=VW+WY

and it is by Addition Property of Equality


5.VX+WY=VW+WY

Above equation is by Substitution Property (2nd use)


6.VX=VW

Above equation is by Substitution Property.

User Nikagra
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