Given:
The voltage across the bulb of the flashlight is: V = 3.00 v
The resistance offered by the bulb of the flashlight is: R = 3.90 Ω
To find:
The amount of current flowing through the bulb.
Step-by-step explanation:
The relation between voltage V, current I, and the resistance R is given by Ohm's law. The expression for Ohm's law is:
![V=IR](https://img.qammunity.org/2023/formulas/physics/college/qyxkyhe6das1rxrn37kfxfu7hnf52d3137.png)
Rearranging the above equation, we get:
![I=(V)/(R)](https://img.qammunity.org/2023/formulas/physics/college/v7qkohrj8ut3qo02mqlnxkdf7mxxaknn9z.png)
Substituting the values in the above equation, we get:
![\begin{gathered} I=\frac{3.00\text{ v}}{3.90\text{ ^^^^2126}} \\ \\ I=0.77\text{ A} \end{gathered}]()
Final answer:
The current flowing through the bulb of the flashlight is 0.77 Ampere.