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Tom Finney · Answer 1 · 2023-07-03T01:14:14+0000

As the statement indicates, the formula to find the area of a trapezoid is

$\begin{gathered} A=(1)/(2)h(b_1+b_2) \\ \text{Where A is the area} \\ h\text{ is the height,} \\ b_1\text{ is a short base and} \\ b_2\text{ is a long base of the trapezoid} \end{gathered}$

Graphically

So, you have

$\begin{gathered} b_1=9\operatorname{cm} \\ b_2=15\operatorname{cm} \\ h=14\operatorname{cm} \end{gathered}$
$\begin{gathered} A=(1)/(2)h(b_1+b_2) \\ A=(1)/(2)(14\operatorname{cm})(9\operatorname{cm}+15\operatorname{cm}) \\ A=(1)/(2)(14\operatorname{cm})(24\operatorname{cm}) \\ A=(7\operatorname{cm})(24\operatorname{cm}) \\ A=168\operatorname{cm}^2 \end{gathered}$

Therefore, the area of the trapezoid is 168 square centimeters.

Im not understanding area base and hight.-example-1

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