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An electron is accelerated by a potential difference of 382.11 kV. How fast is the electron moving if it started from rest?

1 Answer

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The potential difference is related to the kinetic energy of the electron by the formula,

1/2mv^2 = eV

where

m is the mass of the electron

e is the charge of the electron

V is the potential dfference

From the information given,

V = 382.11 x 10^3

m = 9.1 x 10^-31

e = 1.6 x 10^- 19

Thus, we have

1/2 x 9.1 x 10^-31 x v^2 = 1.6 x 10^- 19 x 382.11 x 10^3

45.5 x 10^- 32v^2 = 611.376 x 10^- 16

v^2 = 611.376 x 10^- 16/45.5 x 10^- 32

Taking square root of both sides,

v = 3.67 x 10^8 m/s

The velocity is 3.67 x 10^8 m/s

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