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How far from the foot of a pole 26 meters high, must a 2 meter person stand so that the angle of elevation of the top of the pole is 10 degrees?

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Let's draw an image to represent this question:

Then, in order to calculate the value of x, we can use the tangent relation of the 10° angle.

The tangent relation is given by the length of the opposite side to the angle over the length of the adjacent leg to the angle.

So we have:


\begin{gathered} \tan (10\degree)=(24)/(x) \\ 0.176327=(24)/(x) \\ x=(24)/(0.176327) \\ x=136.11 \end{gathered}

So the horizontal distance from the person to the pole is 136.11 meters.

How far from the foot of a pole 26 meters high, must a 2 meter person stand so that-example-1
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