Given the function that determines the bill:
![b(x)=\begin{cases}0.15x\text{ , }x\leq200^{} \\ \\ 0.10(x-200)+30,\text{ }x>200\end{cases}\text{ }](https://img.qammunity.org/2023/formulas/mathematics/college/7he3y7senbwt98l7jcgmn4gdaok8cjooqd.png)
You know that "x" represents the number of kilowatt-hours (kWh) used in a month
Since you have to find the bill for a person who uses 400 kWh in a month, you can need to use the second equation, because the value of "x" is, in this case:
![x=400](https://img.qammunity.org/2023/formulas/mathematics/high-school/1uqlmcld3mji7m06qjv3ofvfkxl9l2gumh.png)
And:
![400>200](https://img.qammunity.org/2023/formulas/mathematics/college/1sqtcenmijgwt7qtmd0haz5t5wmkc9fwd3.png)
Therefore, substituting that value of "x" into the second equation and evaluating, you get:
![\begin{gathered} b(x)=0.10(x-200)+30 \\ \\ b(400)=0.10(400-200)+30 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/9xdpywzf0ax62domby53u9r1h4xif5d61i.png)
![\begin{gathered} b(400)=0.10(200)+30 \\ \\ b(400)=20+30 \\ \\ b(400)=50 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/x115risyaft825p601x84hs6mgm02a6ivy.png)
Hence, the answer is: Option A.