Question

I need to make a table and find it discrete probability variance and standard deviation with the correct formula

Answer 1

In the table below, I represented p(x) with f(x).

Hence,

`Mean=\Sigma xp(x)=1.89`

Let us now solve for the Variance

Hence,

`Variance=\sigma^2=\Sigma(x-\mu)^2p(x)=1.38`

Let us now solve for the standard deviation

`Standard\text{ deviation=}\sigma=√(\sigma^2)=√(1.38)=1.17`

Hence, the standard deviation is 1.17.