Answer:
Explanation:
To convert the equation in standard form to vertex form, you have to use the completing square method:

Extract a from the first two terms:

Complete the square for the expressions with x. The missing fraction is (b/(2a))². Add and subtract this term in the parabola equation
![\begin{gathered} y=a\cdot\mleft[x^2+(b)/(a)\cdot x+b/\mleft(2a\mright)^2-b/\mleft(2a\mright)^2\mright]+c \\ \text{Simplifying;} \\ y=a\cdot\mleft[\mleft(x+(b)/(2a)\mright)^2-b/\mleft(2a\mright)^2\mright]+c \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/4o91g4kmcw1daflmhwegj39szhzs4nu38e.png)
Substitute the a,b and c terms respectively:
![\begin{gathered} y=a\cdot\mleft[x^2+(b)/(a)\cdot x+b/\mleft(2a\mright)^2-b/\mleft(2a\mright)^2\mright]+c \\ \text{Simplifying;} \\ y=a\cdot\mleft[\mleft(x+(b)/(2a)\mright)^2-b/\mleft(2a\mright)^2\mright]+c \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/4o91g4kmcw1daflmhwegj39szhzs4nu38e.png)