Question

Find the probability distribution of getting sum when a spinner of 3 divisions, labeled from 1 to 3, is spun twice.

Answer 1

We are given that:

The spinner is a 3 divisions spinner. Numbering from 1-3

When the spinner is spun twice, the sum obtained will range from 2-6 as shown below:

`\begin{gathered} nth\colon Spin_1+Spin_2 \\ \\ 1st\colon1+1=2 \\ 2nd\colon1+2=3 \\ 3rd\colon1+3=4 \\ \\ 4th\colon2+1=3 \\ 5th\colon2+2=4 \\ 6th\colon2+3=5 \\ \\ 7th\colon3+1=4 \\ 8th\colon3+2=5 \\ 9th\colon3+3=6 \end{gathered}`

We can thus see the probability distribution from above (I will write it below):

`\begin{gathered} P(sum)=(chance.of.outcome)/(possible.outcome) \\ \\ P(2)=(1)/(9) \\ P(3)=(2)/(9) \\ P(4)=(3)/(9) \\ P(5)=(2)/(9) \\ P(6)=(1)/(9) \end{gathered}`

Therefore, the answer is the third option