Question

What is the impulse experienced by a 24kg dog as he speeds up from 4m/s to 9m/s?

Answer 1

We are asked to determine the impulse of a dog given the change in velocity. To do that we will use the following formula:

`I=p_2-p_1`

This means that the impulse is the change in momentum. Now, we use the formula for momentum:

`p=mv`

Where "m" is the mass and "v" the velocity. Now, we substitute in the formula for impulse:

`I=mv_2-mv_1`

Now, we take "m" as a common factor:

`I=m(v_2-v_1)`

Now, we substitute the values:

`I=(24kg)(9(m)/(s)-4(m)/(s))`

Solving the operation:

`I=120kg(m)/(s)`

Therefore, the impulse is 120 kgm/s