Question

I need help on this please

Answer 1

`(1)/(9)`

Step-by-step explanation

`a^(-2)b^0`

let's remember some properties of the exponents numbers

`\begin{gathered} a^(-n)=(1)/(a^n) \\ a^0=1\text{ ( any number to the zero exponent equals 1)} \end{gathered}`

then,

solve by appling the properties

for a= -3 and b=-3

replace.

`\begin{gathered} a^(-2)b^0 \\ (-3^(-2))(-3^0) \\ ((1)/((-3)^2))(1) \\ ((1)/(3\cdot3))(1) \\ ((1)/(9))(1) \\ (1)/(9) \end{gathered}`

so, the answer is

`(1)/(9)`

I hope this helps you