Question

A heat engine does 23 kJ of work during 1800 s. Find the power supplied by the engine.

Answer 1

Given,

The work done by the engine, W=23 kJ

The time it takes for the engine to do the given amount of the work, t=1800 s

The power is the time rate of change of transfer of energy or the energy transferred in unit time. Thus the power supplied by the engine can be calculated as the ratio of the work done to the time.

Thus the power supplied by the engine is given by,

`P=(W)/(t)`

On substituting the known values,

`\begin{gathered} P=(23*10^3)/(1800) \\ =12.78\text{ W} \end{gathered}`

Thus the power supplied by the engine is 12.78 W.