Given:
The total investment = $36000.
The interest rate of the first investment = 8%.
The interest rate of the second investment = 6%.
The interest rate of the third investment = 9%.
The total interest = $ 2820.
The interest from the first investment was 3 times the interest from the second.
Required:
We need to find the amounts of the three parts of the investment.
Step-by-step explanation:
Let x, y, and z be the amounts of the three parts of the investment.
The total investment = $36000.

The total interest = $ 2820.



The interest from the first investment was 3 times the interest from the second.


Divide both sides by 0.08.







Divide both sides by 0.09.






Divide both sides by 0.58.










Final answer:
The first part of the investment was $ 18103.46.
The second part of the investment was $ 8045.98.
The third part of the investment was $ 9850.56