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What are the demensions of a rectangle if the perimiter is 20 and the area is 24

User Sebastian Oberhoff
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1 Answer

16 votes
16 votes

Answer:

I simply listed the factors of 24, and tested which ones worked in this equation: P = 2a + 2b.

So the factors listed were:

24 x 1

12 x 2

8 x 3

6 x 4

After testing each one of these, 6 and 4 had worked for me.

P = 2(6) + 2(4)

P = 12 + 8

P = 20

Therefore, the dimensions of this rectangle are 6 and 4.

Explanation:

User FiberOptics
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