Question

-19x to the 13th power y to the 4th power76x squared y to the 4th power

Answer 1

`Given,\frac{-19x^{13^{}}y^4}{76x^2y^4^{}}`

Step 1 - Separate the integers from the letters

`\frac{-19^{}}{76}\text{ x }(x^(13))/(x^2)\text{ x }(y^4)/(y^4)`

Step 2 - Simplify the separated terms/fractions

`\begin{gathered} (-19)/(76)\text{ }=(-1)/(4) \\ (x^(13))/(x^2)\text{ }=x^(11) \\ (y^4)/(y^4)=1^{} \\ \end{gathered}`

Step 3 - Combine all the simplified terms/fractions from step2, and multiply then out the numerators and denominators

`(-1)/(4)\text{ x }(x^(11))/(1)\text{ x }(1)/(1)=(-x^(11))/(4)\text{ }`

Therefore, the answer to the question is

`(-x^(11))/(4)\text{ or }(-1)/(4)x^(11)`