Given:
The frequency of photon is 9.48 × 10^13 Hz.
To find:
The energy of a photon.
Step-by-step explanation:
The energy of a photon is related to its frequency as,

here, h is called Planck's constant whose value is 6.63 × 10^(-34) J s, and ν is the frequency of the photon.
Substituting the values in the above equation, we get:

Simplifying above equation, we get:

Thus, the value of the photon's energy is 6.28 × 10^(-20) J.
Final answer:
The energy of photon is 6.28 × 10^(-20) J.