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What would be the multiplier if oxygen had come out to be 2.33 mol?234

User Sikachu
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1 Answer

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For this problem, we need to find an integer for the number of moles of oxygen. Let's see the results by multiplying 2.33 and 2, 3, 4:


\begin{gathered} 2.33\text{ mol}\cdot2=4.66\text{ moles.} \\ 2.33\text{ mol}\cdot3=6.99\text{ moles}\approx7\text{ moles.} \\ 2.33\text{ mol}\cdot4=9.32\text{ moles.} \end{gathered}

You can note that if we multiply 2.33 moles by three (3), we obtain an integer of the number of moles.

User Vetterjack
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