First, we can note that the greatest common factor of 50 and 98 is 2, so we can rewrite our expression as:
![2(25x^2-49)](https://img.qammunity.org/2023/formulas/mathematics/college/yx098w8cbqqtahrv124lmfhysa78vxr8p5.png)
Now, the term into the parentheses is a difference of 2 squares because
![25x^2-49=(5x+7)(5x-7)](https://img.qammunity.org/2023/formulas/mathematics/college/zqddgpr4g7z6a4oqjpffkkvv8w2kkpeetn.png)
By substituting this result into the first expression from above, we get
![2(25x^2-49)=2(5x+7)(5x-7)](https://img.qammunity.org/2023/formulas/mathematics/college/jje1u5yvq2mef846bi6d7pj1ysuz2k6a1t.png)
Therefore, the answer is:
![2(5x+7)(5x-7)](https://img.qammunity.org/2023/formulas/mathematics/college/uv9rhxux9rexmxm77z66hyo9zsdbnsnbhf.png)