Given
The engines of a plane are pushing it due north at a rate of 300 mph, and the wind is pushing the plane 20° west of north at a rate of 40 mph.
To find the magnitude of the resultant vector.
Step-by-step explanation:
It is given that,
Then,
![\begin{gathered} Plane:300(\cos90\degree,\sin90\degree) \\ Wind:40(\cos110\degree,\sin110\degree) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/cjq6hkbr8vy6cr6poqn940xnju0d2ds1aw.png)
That implies,
![\begin{gathered} Plane:300(0,1)=(0,300) \\ Wind:40(-0.34,0.94)=(-13.6,37.59) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/7bg1jbkiak0tunuux6ahr606qwzd5zf1y2.png)
Adding these two points implies,
![\begin{gathered} R=(0-13.6,300+37.59) \\ =(-13.6,337.6) \\ \Rightarrow|R|=√((-13.6)^2+(337.6)^2) \\ =√(184.96+113973.76) \\ =√(114158.72) \\ =337.87 \\ =337.9mph \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/rh0g8m631pdrqemwehflc4fj1kojs1tkyd.png)
Hence, the magnitude of R is 337.9mph.