Given inequalities:
![\begin{gathered} \text{x + y }\leq\text{ 6} \\ x\text{ + 2y }\leq\text{ 8} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/aez6kyn7bjpqods4y51unkabfbgpecgz77.png)
We would be plotting the graph of each inequality combine their solutions.
![x\text{ + y }\leq\text{ 6}](https://img.qammunity.org/2023/formulas/mathematics/college/ugby3c7e7mxps651dm2gebgduay9uez18l.png)
We have the equation : x + y = 6 from the inequality
We need two points to draw thw boundary line. Hence:
When x = 0:
![\begin{gathered} 0\text{ + y = 6} \\ y\text{ =6} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/g6yepo5bgx0d4gppnyac0r6ku3z17ljt6j.png)
When y = 0:
![\begin{gathered} x\text{ + 0 = 6} \\ x\text{ =6} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/kucs8q46sxjcapa794aqhk5q7x7faj9rp4.png)
We have the points : (0,6) and (6,0)
Now that we have the boundary line points, we can show the region that satisfies the inequality as shown below:
The shaded region is the solution to the inequality
Similarly for the second inequality:
![x\text{ + 2y }\leq\text{ 8}](https://img.qammunity.org/2023/formulas/mathematics/college/ubjirizd407acp37btaz55xodto00wqfn7.png)
We need two points to draw the boundary line: x + 2y = 8. Hence:
When x = 0:
![\begin{gathered} 0\text{ + 2y = 8} \\ \text{Divide both sides by 2} \\ y\text{ =4} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/hxm8joen0c1n83osf6b7o53ssofln1ejqv.png)
When y = 0:
![\begin{gathered} x\text{ + 2}*0\text{ = 8} \\ x\text{ +0 = 8} \\ x\text{ =8} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/1da5zoav5mn62oy2hu2kl5ilrxywctbuka.png)
We have the points: (0,4) and (8,0)
Now that we have the boundary line points, we can show the region that satisfies the inequality as shown below:
The shaded region is the solution to the inequality
Combining the solutions, we have:
Hence, the graph that best represents the solution to the system of inequalities is the graph in Option D
Answer: Option D