To solve this question, we will need the reaction that produces glucose:
6CO2 + 6H2O → C6H12O6 + 6O2 (don't forget please to balance it)
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Data:
135 mg of C6H12O6 = one leaf of a tree
We want to calculate the amount of CO2 to get this leaf.
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Procedure:
135 mg = 0.135 g (1000 mg = 1 g)
We also need the molar mass of:
C6H12O6 => 180 g/mol
CO2 => 44 g/mol
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Procedure:
6 x 44 g CO2 --------- 180 g C6H12O6
X --------- 0.135 g
X = 0.135 g x 6 x 44 g/180 g = 0.198 g
0.198 g = 1.98x10^-1 g (scientific notation)
Answer: c. 1.98x10^-1 g