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A motorcycle's front wheel has a larger diameter than the back wheel to better takeand manage impact. The radius of the front tire of a motorcycle is 19 inches and theback tire is 16 inches. What is the angular speed of the front tire in rpm if the linearspeed is 68 feet/second? Use 3.14 for M, round to the nearest whole number, andenter the number only.

User Ubuntuuber
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1 Answer

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The formula for calculating angular speed is expressed as

w = v/r

where

w is the angular speed

v is the linear velocity

r is the radius of the wheel

We are considering the front tire. From the information given,

r = 19 inches

We would convert it to meters

Recall, 1 inch = 0.0254 m

19 inches = 19 x 0.0254 = 0.4826 m

v = 68 ft/s

We would convert 68 ft to meters

Recall, 1 foot = 0.3048 m

68 feet = 68 x 0.3048 = 20.7268

thus, v = 20.7268m/s

By substituting these values into the formula, we have

w = 20.7268/0.4826 = 42.95 rad/s

We need to convert to rpm. Let x rpm = 42.95 rad/s

1 rpm = 2pi/60 rad/s

Then,

x rpm = 42.95 rad/s

By crossmultiplying, we have

1 * 42.95 = x * 2pi/60

x = 42.95/2pi/60

If pi = 3.14, then

x = 42.95/2 * 3.14/60 = 42.95/0.105

x = 409 rpm

The angular speed of the front tire is 409 rpm

User Megan Sime
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