Question

The reason for the trend in the previous question is because Bromine is _________electron density from the carbon the proton is on, resulting in the proton being ___________, thus the proton nuclei is_________ effected by the applied magnetic field leading to a greater difference in energy of the nuclei's spin states.

Answer 1

Step-by-step explanation:

From this question, we are to fill in the blanks with the appropriate correct answers.

`\text{The reason for the trend in the previous question is because Bromine is } \mathbf{withdrawing}`
`\text{electron density from the carbon the proton is on, resulting in the proton being }\mathbf{deshielded, }`
`\text{thus the proton nuclei is} \ \ \mathbf{more} \ \ \text{effected by the applied magnetic field leading to a }`

`\text{greater difference in energy of the nuclei's spin states.}`

NOTE: that the electron-withdrawing groups decrease the electron density around the proton nucleus and therefore the nucleus feels the external magnetic field more. Hence, it requires a larger frequency to attain resonance(downfield).