Question

Determine the range of the function f(x)=3/2 (x+2) when the domain is {-4,-2,2?

Answer 1

`f(x)=(3)/(2)(x+2)`

Let's evaluate the function for the interval:

[-4,-2.2]

`\begin{gathered} f(-4)=(3)/(2)(-4+2) \\ f(-4)=(3)/(2)(-2) \\ f(-4)=-3 \end{gathered}`
`\begin{gathered} f(-2.2)=(3)/(2)(-2.2+2) \\ f(-2.2)=-0.3 \end{gathered}`

Therefore, the range is:

`R\colon\lbrack-3,-0.3\rbrack`