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the dimensions of triangle B are twice the dimensions of triangle A the area of triangle A is 15cm what is the area of triangle b

the dimensions of triangle B are twice the dimensions of triangle A the area of triangle-example-1
User Nelsch
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1 Answer

4 votes

Let:

A1 = Area of triangle A

A2 = Area of triangle B

Since the dimensions of triangle B are twice the dimensions of triangle A, then:


\begin{gathered} h2=2h1 \\ b2=2b1 \end{gathered}

Where:

h1 = height of triangle A

h2 = height of triangle B

b1 = base of triangle A

b2 = base of triangle B

The area of the triangle B is given by:


\begin{gathered} A2=(b2\cdot h2)/(2) \\ A2=((2b1\cdot2h1))/(2) \\ A2=2b1\cdot h1 \\ where \\ b1\cdot h1=2A1 \\ b1\cdot h1=2(15\operatorname{cm})=30cm^2 \\ A2=2(30cm^2) \\ A2=60cm^2 \end{gathered}

Answer:

60 cm²

User Tarif Haque
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