Question

SOMEONE PLEASE HELP IM FAILING THIS CLASS

Given the similar triangles, find the value of x.
AABC~AAGF

Answer 1

x = 4

Explanation:

Given that ∆ABC ~ ∆AGF, it follows that their lengths would be proportional to each other. This implies that:

AB/AG = AC/A F

Substitute

55/22 = 30/(4x - 4)

5/2 = 30/(4x - 4)

Cross multiply

5(4x - 4) = 30(2)

20x - 20 = 60

20x - 20 + 20 = 60 + 20

20x = 80

Divide both sides by 20

20x/20 = 80/20

x = 4