Question

The point (-6, 4) lies on a straight line that has a gradient of -2. What is the

equation of this line?

Answer 1

Given:

Point on straight line = (-6,4)

Gradient = -2

To find:

The equation of the line.

Solution:

Point-slope form: If a line passes through the point
`(x_1,y_1)` with slope m, then the equation of the line is

`y-y_1=m(x-x_1)`

The line passes through the point (-6,4) with slope -2. So, the equation of the line is:

`y-4=-2(x-(-6))`

`y-4=-2(x+6)`

`y-4=-2x-12`

Adding 4 on both sides, we get

`y-4+4=-2x-12+4`

`y=-2x-8`

Therefore, the equation of the line is
`y=-2x-8`.