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Vasili · Answer 1 · 2023-08-10T02:53:25+0000

Solution.

We are required to find the area triangle to the nearest tenth.

Two sides of the triangle and an included angle is given

$\begin{gathered} Thus,\text{ the area of the triangle is }(1)/(2)absin\theta \\ Where\text{ a,b= sides of the triangle} \\ \theta=included\text{ angle} \end{gathered}$
$\begin{gathered} For\text{ the triangle given, } \\ a=15m \\ \text{ b=8m} \\ \theta=108 \end{gathered}$
$Area=(1)/(2)\text{ x 15 x 8 x sin108}$
$\begin{gathered} Area=57.0623m^2 \\ Area\text{ of the triangle = 57.1m}^2(nearest\text{ tenth} \end{gathered}$

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