Question

Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar.The focus of a parabola is (0,–1). The directrix is the line y = 0 What is the equation of the parabola in vertex form?- k²thIn the equation =the value of pisThe vertex of the parabola is the pointThe equation of this parabola in vertex form is y=12 - 1

Answer 1

The Solution:

Given the equation of the parabola in vertex form:

`y=ax^2-1`

`y=(1)/(4p)(x-h)^2+k`

`\begin{gathered} \text{ Focus: (h,K+p)=(0,-1)} \\ h=0 \\ k+p=-1\ldots\text{eqn}(1) \end{gathered}`

By directrix:

`\begin{gathered} y=k-p \\ 0=k-p \\ k-p=0\ldots eqn(2) \end{gathered}`

Solving eqn(1) and eqn(2) simultaneously, we get

`\begin{gathered} 2k=-1 \\ \\ k=-(1)/(2)=-0.5 \end{gathered}`

So, the directrix is:

`(h,k)=(0,-0.5)`

So, the equation of the parabola is

`\begin{gathered} y=(1)/(4(-0.5))x^2-0.5 \\ \\ y=-0.5x^2-0.5 \end{gathered}`

So, the value of p is -0.5

Thus, the equation of the parabola in vertex form is:

`y=-0.5x^2-0.5`