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If the perimeter of a rectangular lot is equal to100 meters. and its width is 18.5 meters, what isthe length of the lot?HINT: p= 21 +2 wShow your work on the left then type your finalanswer below.

User Tim Pierce
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1 Answer

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Perimeter = 100m = P

width = w = 18.5

length = ?

Equation

P = 2w + 2l

Substitution

100 = 2(18.5) + 2l

Solve for l

100 = 37 + 2l

100 - 37 = 2l

63 = 2l

l = 63/2

l = 31.5 m

Length = 31.5 m

User Baku
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