Question

Find the value D(−1), where D is defined below.D(x)=x^2−2x−1

Answer 1

`D(-1)=2`

Explanation:

We have the following equation:

`D\mleft(x\mright)=x^2-2x-1`

We calculate the value of the function when the value of x is equal to -1, we replace:

`\begin{gathered} D(-1)=(-1)^2-2\cdot(-1)-1 \\ D(-1)=1+2-1 \\ D(-1)=2 \end{gathered}`